在非映射元素上产生JAXB错误
我正试图做相反的事情:JAXB - 忽略元素
这是我想用JAXB解析XML的POJO,我想JAXB如果它没有找到一个给定元素匹配的Java属性失败。 我知道我可以做架构验证,但我宁愿不这样做。
例:
@XmlRootElement(name="Dog")
public class Dog {
private String name;
public String getName() {return name;}
public String setName(String name) {this.name = name};
}
这个XML会失败:
<Dog>
<id>blah</id>
<name>Stuff</name>
</Dog>
因为没有id
Java属性
您可以利用ValidationEventHandler
来获取您正在查找的行为。 意外的元素被视为默认情况下被忽略的警告。 为了支持你的用例,你可以提供一个ValdidationEventHandler
,它在警告时失败(见下文)。
演示
package forum10721257;
import java.io.File;
import javax.xml.bind.*;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Dog.class);
File xml = new File("src/forum10721257/input.xml");
Unmarshaller unmarshaller = jc.createUnmarshaller();
unmarshaller.setEventHandler(new ValidationEventHandler () {
@Override
public boolean handleEvent(ValidationEvent event) {
return false;
}
});
Dog dog = (Dog) unmarshaller.unmarshal(xml);
}
}
JAXB RI异常
Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"id"). Expected elements are <{}name>
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:647)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:243)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:238)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportUnexpectedChildElement(Loader.java:105)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.childElement(Loader.java:90)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.StructureLoader.childElement(StructureLoader.java:236)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext._startElement(UnmarshallingContext.java:483)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:465)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.SAXConnector.startElement(SAXConnector.java:135)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.startElement(AbstractSAXParser.java:506)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:376)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2715)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:607)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:116)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:488)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:835)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:764)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:123)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1210)
at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:568)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:202)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:174)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:157)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:162)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:171)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:189)
at forum10721257.Demo.main(Demo.java:26)
EclipseLink JAXB(MOXy)
我们最近将此行为添加到MOXY。 您将需要使用EclipseLink 2.4.0或2.3.3。 每晚可以从以下地点获得建筑物:
UPDATE
我需要从你的问题中调整Dog
类。 以下是我用过的。
狗
package forum10721257;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name="Dog")
public class Dog {
private String name;
public String getName() {return name;}
public void setName(String name) {this.name = name;}
}
我能够验证丢失的Java属性(无模式)的唯一方法是将XML解组到我的POJO,然后使用相同的POJO将其重新编码为XML并进行比较。
下面是一个使用XMLUnit的例子,它有助于忽略顺序和空白问题。
@Test
public void testSerialization() throws Exception {
XMLUnit.setIgnoreWhitespace(true);
EventSearchResults r =
JAXB.unmarshal(getClass().getResourceAsStream("/EventSearchResults.xml"),
EventSearchResults.class);
StringWriter sw = new StringWriter();
JAXB.marshal(r, sw);
String expected =
IOUtils.toString(getClass().getResourceAsStream("/EventSearchResults.xml"), "UTF-8");
String actual = sw.toString();
//System.out.println(expected);
System.out.println(actual);
assertXMLEqual(expected, actual);
}
这并不理想,但大部分都适用于单元测试。
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