If statement structure in PHP
I keep getting an error with the following bit of code. It is probably some small thing but I don't see what is wrong.
while($row = mysql_fetch_array($result)) { $varp = $row['ustk_retail']; if ($varp<80000) { $o1 = 1; } if (($varp=>80000) && ($varp<100000)) { $o2 = "1"; } if (($varp=>100000) && ($varp<120000)) { $o3 = "1"; } if (($varp=>120000) && ($varp<140000)) { $o4 = "1"; } if (($varp=>140000) && ($varp<160000)) { $o5 = "1"; } if (($varp=>160000) && ($varp<180000)) { $o6 = "1"; } if (($varp=>180000) && ($varp<200000)) { $o7 = "1"; } if (($varp=>200000) && ($varp<220000)) { $o8 = "1"; } if (($varp=>220000) && ($varp<240000)) { $o9 = "1"; } if (($varp=>240000) && ($varp<260000)) { $o10 = "1"; } if (($varp=>260000) && ($varp<280000)) { $o11 = "1"; } if (($varp=>280000) && ($varp<300000)) { $o12 = "1"; } if ($varp>=300000) { $o13 = "1"; } }
Greater than or equal to is >=
sign, not =>
Update:
You are right. It's small but hard to find mistake.
It took me to split whole line into pieces to see where the problem is:
<?php
if
(
$varp
=>
80000
)
So, it says parse error on line 5 and I had to doublecheck this operator.
Of course, at first I separated the problem line from the rest of the code to be certain.
Running php -l
(lint) on your code I get a
Parse error: syntax error, unexpected T_DOUBLE_ARROW
The T_DOUBLE_ARROW
token is what PHP expects when assigning array values to array keys.
When comparing for Greater than or equal to the PHP Parser expects T_IS_GREATER_OR_EQUAL
, meaning you have to use >=
instead of =>
.
See
你有一个表达错误。
$varp=>220000 // is not a valid php expression
=> operator is used to assign values in arrays like:
$x = array( 'foo' => 'bar');
>= is the comparation assigment greater than or equal
链接地址: http://www.djcxy.com/p/12034.html
上一篇: 如何检查文本框是否为空并且值小于500
下一篇: 如果PHP中的语句结构