我如何迭代JSON结构？
这个问题在这里已经有了答案：
来自jQuery文档：
var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };
jQuery.each(arr, function() {
$("#" + this).text("My id is " + this + ".");
return (this != "four"); // will stop running to skip "five"
});
jQuery.each(obj, function(i, val) {
$("#" + i).append(document.createTextNode(" - " + val));
});
var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "classd": "child-of-10"}];
for (var i = 0; i < arr.length; i++){
var obj = arr[i];
for (var key in obj){
var attrName = key;
var attrValue = obj[key];
}
}
var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "class": "child-of-10"}];
for (var i = 0; i < arr.length; i++){
document.write("<br><br>array index: " + i);
var obj = arr[i];
for (var key in obj){
var value = obj[key];
document.write("<br> - " + key + ": " + value);
}
}使用foreach ：
<html>
<body>
<script type="text/javascript">
var mycars = [{name:'Susita'}, {name:'BMW'}];
for (i in mycars)
{
document.write(mycars[i].name + "<br />");
}
</script>
</body>
</html>
将导致：
Susita
BMW