How to find if an array contains a specific string in JavaScript/jQuery?
This question already has an answer here:
You really don't need jQuery for this.
var myarr = ["I", "like", "turtles"];
var arraycontainsturtles = (myarr.indexOf("turtles") > -1);
or
function arrayContains(needle, arrhaystack)
{
return (arrhaystack.indexOf(needle) > -1);
}
It's worth noting that array.indexOf(..) is not supported in IE < 9, but jQuery's indexOf(...) function will work even for those older versions.
jQuery offers $.inArray :
Note that inArray returns the index of the element found, so 0 indicates the element is the first in the array. -1 indicates the element was not found.
var categoriesPresent = ['word', 'word', 'specialword', 'word'];
var categoriesNotPresent = ['word', 'word', 'word'];
var foundPresent = $.inArray('specialword', categoriesPresent) > -1;
var foundNotPresent = $.inArray('specialword', categoriesNotPresent) > -1;
console.log(foundPresent, foundNotPresent); // true false<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>Here you go:
$.inArray('specialword', arr)
This function returns a positive integer (the array index of the given value), or -1 if the given value was not found in the array.
Live demo: http://jsfiddle.net/simevidas/5Gdfc/
You probably want to use this like so:
if ( $.inArray('specialword', arr) > -1 ) {
// the value is in the array
}
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