随机化整数行为

看到这个问题后,我开始怀疑:是否可以编写一个类似随机整数的类?

我设法用dir()找到一些可覆盖的方法:

class RandomInt(int):
    def __add__(self, other):
        return randint(1, 100) + other

    def __mul__(self, other):
        return randint(1, 100) * other

    def __div__(self, other):
        return randint(1, 100) / other

    def __sub__(self, other):
        return randint(1, 100) - other

    def __repr__(self):
        return str(randint(1, 100))

但我觉得有一种更优雅的方法可以将randint(1, 100)注入到接受self参数的每个方法中。

有没有办法做到这一点,而不用从头重写整个int类?

就像是:

>>> x = RandomInt()
>>> x + 1
2
>>> x + 1
74
>>> x * 4
152

这是一个不同的答案,因为它与我发布的另一个截然不同。 (我觉得这是值得分开的)

代码:

class RandomInt:
    def __getattr__(self, name):
        attr = getattr(int, name, '')
        if attr != '':
            def wrapper(*args, **kw):
                return attr(random.randint(1, 100), *args, **kw)
            return wrapper
        else:
            raise AttributeError(
                    "'{0}' object has no attribute '{1}'".format('RandomInt',name))

示例运行:

>>> x = RandomInt()
>>> x
88
>>> 1 + x # __radd__
67
>>> x*100 # __mul__
1900
>>> x+5 # __add__
50
>>> x-1000 # __sub__
-945
>>> x//5 # __floordiv__
8
>>> float(x) # __float__
63.0
>>> str(x) # __str__
'75'
>>> complex(x) # __complex__
(24+0j)
>>> sum([x]*10)
573

有改进的余地:

>>> x + x

Traceback (most recent call last):
  File "<pyshell#1456>", line 1, in <module>
    x + x
TypeError: unsupported operand type(s) for +: 'instance' and 'instance'

x*xx/x和类似的相同


这次的另一个版本,类似于@ gatto的回答:

import random, inspect

class RandomInt:
    def __init__(self):
        def inject(attr):
            def wrapper(*args, **kw):
                args = list(args)
                for i,x in enumerate(args):
                    if isinstance(x, RandomInt):
                        args[i] = x+0
                return attr(random.randint(1,100), *args, **kw)
            return wrapper

        for name in dir(int):
            attr = getattr(int, name)
            if inspect.ismethoddescriptor(attr):
                setattr(self, name, inject(attr))

这个支持:

>>> x + x
49
>>> x // x
2
>>> x * x
4958
>>> x - x
77
>>> x ** x
467056167777397914441056671494001L
>>> float(x) / float(x)
0.28

还有另一个版本,它使用类属性来克服新式/旧式问题(谢谢@gatto):

import random, inspect

class RandomInt(object):
    pass

def inject(attr):
    def wrapper(*args, **kw):
        args = list(args)
        for i,x in enumerate(args):
            if isinstance(x, RandomInt):
                args[i] = random.randint(1,100)
        return attr(*args, **kw)
    return wrapper

for name in dir(int):
    attr = getattr(int, name)
    if inspect.ismethoddescriptor(attr):
        setattr(RandomInt, name, inject(attr))

输出:

>>> x
86
>>> x
22
>>> x * x
5280
>>> [1] * x
[1, 1, 1, 1, 1, 1]
>>> x * '0123'
'0123012301230123'
>>> s[x] # s = '0123456789' * 10
'5'

import inspect
from random import randint

class SelfInjecter(type):
    def __new__(self, *args, **kw):
        cls = type(*args, **kw)
        factory = cls.__factory__

        def inject(attr):
            def wrapper(self, *args, **kw):
                return attr(factory(self), *args, **kw)
            return wrapper

        for name in dir(cls):
            attr = getattr(cls, name)

            if inspect.ismethoddescriptor(attr):
                setattr(cls, name, inject(attr))

        return cls

class RandomInt(int):
    __metaclass__ = SelfInjecter
    __factory__ = lambda self: randint(1, 100)

x = RandomInt()
print x + 3, x - 3, x * 3, repr(x)

上面的代码有一些问题。

正如小学生所建议的那样,以下方法无法正常工作:

>>> print x * x
0

如果可能,我们需要将所有参数转换为新类型的RandomInt

def factory(x):
    if isinstance(x, cls):
        return cls.__factory__(x)
    return x

def inject(attr):
    def wrapper(*args, **kw):
        args = [factory(x) for x in args]
        kw = {k: factory(v) for k, v in kw}
        return attr(*args, **kw)

    return wrapper

序列乘法和索引也不能按预期工作:

>>> [1] * x, x * '123', '123'[x]
([], '', '1')

这是因为Python不会将__index__用于int -inherited类型:

class Int(int):
    def __index__(self):
        return 2

>>> x = Int(1)
>>> '012'[x], '012'[x.__index__()]
('1', '2')

以下是Python 2.7.4实现的代码:

/* Return a Python Int or Long from the object item
   Raise TypeError if the result is not an int-or-long
   or if the object cannot be interpreted as an index.
*/
PyObject *
PyNumber_Index(PyObject *item)
{
    PyObject *result = NULL;
    if (item == NULL)
        return null_error();
    if (PyInt_Check(item) || PyLong_Check(item)) {
        Py_INCREF(item);
        return item;
    }
    if (PyIndex_Check(item)) {
        result = item->ob_type->tp_as_number->nb_index(item);
        if (result &&
            !PyInt_Check(result) && !PyLong_Check(result)) {
            PyErr_Format(PyExc_TypeError,
                         "__index__ returned non-(int,long) " 
                         "(type %.200s)",
                         result->ob_type->tp_name);
            Py_DECREF(result);
            return NULL;
        }
    }

正如你所看到的,它首先检查intlong ,然后尝试调用__index__

解决方案是从int继承object并克隆/包装属性,或者实际上我更喜欢Schoolboys的答案,我猜也可以用类似的方式纠正它。


一个想法是有一个__call__方法,返回一个随机数。

class RandomInt(int):
    def __call__(self):
        return random.randint(1, 100)
    def __add__(self, other):
        return self() + other

    def __mul__(self, other):
        return self() * other

    def __div__(self, other):
        return self() / other

    def __sub__(self, other):
        return self() - other

    def __repr__(self):
        return str(self())

示例运行

>>> x = RandomInt()
>>> x * 3
81
>>> x + 3
56
>>> x - 4
68
>>> x / 4
2
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