Optimistic way of checking null references in java

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Avoiding != null statements 58 answers

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add("x_Amount", amount);
add("x_Currency_Code", currency);
add("x_Exp_Date", expDate);

void add(String name, String value)
{
    if(value!=null && !value.isEmpty())
        AIMRequest.put(name, value); 
}

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According your if 's, conditions you are comparing String s, so make a method:

public boolean isValid(String s) {
    return s != null && s != "" && !s.isEmpty();
}

If you want to compare objects with this methods change the signature public boolean isValid(Object o) ,

and your code will be clean as this:

if(isValid(amount))
        AIMRequest.put("x_Amount", amount);

if(isValid(currency)
        AIMRequest.put("x_Currency_Code", currency);

if(isValid(expDate)
        AIMRequest.put("x_Exp_Date", expDate);

But if you can collect all objects in an array :

public boolean isValid(Object[] os) {
    for (String s : os) {
        boolean isValid = s != null && s != "" && !s.isEmpty();
        if (!isValid) return false;
    }
    return true;
}

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This method will accept an array of objects and loop through them to check for any undefined object or null or empty.

public Object[] checkForNull(Object[] objects){
    for(int i = 0;i<objects.length;i++){
    //check all conditions for null empty or no data.
        if(objects[i]!= null && objects!= "" && !objects[i].isEmpty()) 
             object[i] = "UNDEFINED";
    return objects[];
}

So now you can pass all the objects u want to check for empty or undefined or null and then in your case where u want to use all u need to do is check: if(object == "UNDEFINED")

Hope it helps.

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