Regular expression that doesn't contain certain string

 

This question already has an answer here:

  • Regular expression to match a line that doesn't contain a word? 25 answers

    • In general it's a pain to write a regular expression not containing a particular string. We had to do this for models of computation - you take an NFA, which is easy enough to define, and then reduce it to a regular expression. The expression for things not containing "cat" was about 80 characters long.

    Edit: I just finished and yes, it's: 

    aa([^a] | a[^a])aa

    Here is a very brief tutorial. I found some great ones before, but I can't see them anymore.

    By the power of Google I found a blogpost from 2007 which gives the following regex that matches string which don't contains a certain substring: 

    ^((?!my string).)*$

    It works as follows: it looks for zero or more (*) characters (.) which do not begin (?! - negative lookahead) your string and it stipulates that the entire string must be made up of such characters (by using the ^ and $ anchors). Or to put it an other way:

    The entire string must be made up of characters which do not begin a given string, which means that the string doesn't contain the given substring.

    All you need is a reluctant quantifier: 

    regex: /aa.*?aa/

aabbabcaabda   => aabbabcaa

aaaaaabda      => aaaa

aabbabcaabda   => aabbabcaa

aababaaaabdaa  => aababaa, aabdaa

    You could use negative lookahead, too, but in this case it's just a more verbose way accomplish the same thing. Also, it's a little trickier than gpojd made it out to be. The lookahead has to be applied at each position before the dot is allowed to consume the next character. 

    /aa(?:(?!aa).)*aa/

    As for the approach suggested by Claudiu and finnw, it'll work okay when the sentinel string is only two characters long, but (as Claudiu acknowledged) it's too unwieldy for longer strings.

    链接地址: http://www.djcxy.com/p/13372.html

    上一篇: RegEx排除特定的字符串常量

    下一篇: 正则表达式不包含某些字符串