Match All Occurrences of a Regex
Is there a quick way to find every match of a regular expression in Ruby? I've looked through the Regex object in the Ruby STL and searched on Google to no avail.
使用scan应该做的诀窍是：
string.scan(/regex/)
For finding all the matching strings, Use scan method of String class.
str = "A 54mpl3 string w1th 7 numb3rs scatter36 ar0und"
str.scan(/d+/)
#=> ["54", "3", "1", "7", "3", "36", "0"]
If you rather want MatchData which is the type of the object returned by, match method of Regexp classs, use the following
str.to_enum(:scan, /d+/).map { Regexp.last_match }
#=> [#<MatchData "54">, #<MatchData "3">, #<MatchData "1">, #<MatchData "7">, #<MatchData "3">, #<MatchData "36">, #<MatchData "0">]
The benefit of having MatchData is that you can use methods like offset
match_datas = str.to_enum(:scan, /d+/).map { Regexp.last_match }
match_datas[0].offset(0)
#=> [2, 4]
match_datas[1].offset(0)
#=> [7, 8]
Refer these questions too if you'd like to know more
How do I get the match data for all occurrences of a Ruby regular expression in a string?
Ruby regular expression matching enumerator with named capture support
How to find out the starting point for each match in ruby
Reading about special variables $& , $' , $1 , $2 in ruby will be super helpful.
if you have a regexp with groups :
str="A 54mpl3 string w1th 7 numbers scatter3r ar0und"
re=/(d+)[m-t]/
You use scan of string method to find matching groups:
str.scan re
#> [["54"], ["1"], ["3"]]
To find matching pattern:
str.to_enum(:scan,re).map {$&}
#> ["54m", "1t", "3r"]
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