Initializing variables (int32) inside switch statement

This question already has an answer here:

Why can't variables be declared in a switch statement? 23 answers

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Try adding {} :

default:
{
    int32 x = 1;
    doSomething(x);
    break;
}

According to the standard:

It is possible to transfer into a block, but not in a way that bypasses declarations with initialization. A program that jumps 91 from a point where a variable with automatic storage duration is not in scope to a point where it is in scope is ill-formed unless ....

void f() {
    // ...
    goto lx; // ill-formed: jump into scope of a
        // ...
    ly:
        X a = 1;
        // ...
    lx:
        goto ly; // OK, jump implies destructor
                 // call for a followed by construction
                 // again immediately following label ly
}

91) The transfer from the condition of a switch statement to a case label is considered a jump in this respect.

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