What's the fastest way to find the number of spaces in an NSString?

I have an NSString and I want to find the number of spaces in it. What's the fastest way?

---

也许不是最快的执行，但最快输入：

[[myString componentsSeparatedByString:@" "] count]-1

---

I tried this and it seems to work. It might be possible to optimize, but you only need to worry about that if it's absolutely necessary.

NSUInteger spacesInString(NSString *theString) {
    NSUInteger result = 0;
    if ([theString length]) {
        const char *utfString = [theString UTF8String];
        NSUInteger i = 0;
        while (utfString[i]) {
            if (' ' == utfString[i]) {
                result++;
            }
            i++;
        }
    }

    return result;
}

---

我没有测试过这个，但它似乎应该是我的头顶。

int spacesCount = 0;

NSRange textRange;
textRange = [string rangeOfString:@" "];

if(textRange.location != NSNotFound)
{
    spacesCount = spacesCount++;
}

NSLog(@"Spaces Count: %i", spacesCount);

链接地址: http://www.djcxy.com/p/14926.html

上一篇: 在文本字段中显示Unicode字符

下一篇: 什么是在NSString中查找空格数的最快方法？