Extract few substrings from one string using a single regex
As an input I get a string like "0123456789@site.com". All parts are variable. Only rules are that the number of digits in front is always 10 and then there is "@". I need a regex which will allow me to extract "12345" (ie digits from positions 2 to 6) and "site.com" substrings. For example, in above case the result could be either "12345site.com" or "12345:site.com". Can it be done with a single regular expression? How can we skip first digit and digits from positions 7 to 10 and '@'? Examples in Java will be appreciated.
If i understood you correctly, this regex will do
d(d{5})d{4}@(.+)
and then use
matcher.group(1) + matcher.group(2)
to concatenate the groups.
Java code:
public static void main(String[] args) {
String s = "0123456789@site.com";
String patternString = "d(d{5})d{4}@(.+)";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(s);
if (matcher.matches()) {
System.out.println(matcher.group(1) + matcher.group(2));
// shows "12345site.com"
}
}
特别针对您的输入模式：
d{1}(d{5})d*@(.*)
2 capturing groups:
group 1: (d{5})
group 2: (.*)
Input: 0123456789@site.com
Output: 12345
site.com
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