platform way of getting information from Python's OSError?
On a simple directory creation operation for example, I can make an OSError like this:
(Ubuntu Linux)
>>> import os
>>> os.mkdir('foo')
>>> os.mkdir('foo')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OSError: [Errno 17] File exists: 'foo'
Now I can catch that error like this:
>>> import os
>>> os.mkdir('foo')
>>> try:
... os.mkdir('foo')
... except OSError, e:
... print e.args
...
(17, 'File exists')
Is there a cross-platform way that I can know that that the 17 or the 'File Exists' will always mean the same thing so that I can act differently depending on the situation?
(This came up during another question.)
The errno attribute on the error should be the same on all platforms. You will get WindowsError exceptions on Windows, but since this is a subclass of OSError the same " except OSError: " block will catch it. Windows does have its own error codes, and these are accessible as .winerror , but the .errno attribute should still be present, and usable in a cross-platform way.
Symbolic names for the various error codes can be found in the errno module. For example,
import os, errno
try:
os.mkdir('test')
except OSError, e:
if e.errno == errno.EEXIST:
# Do something
You can also perform the reverse lookup (to find out what code you should be using) with errno.errorcode . That is:
>>> errno.errorcode[17]
'EEXIST'
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