How to generate Unique ID without form submission in php ajax

This question already has an answer here:

Create GUID / UUID in JavaScript? 49 answers

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您可以将onchange事件附加到您的输入。

<form method="post" action="">
<input type="text" name="name" id="name" onchange="my_validate_func()">
<input type="text" name="phone" id="phone" onchange="my_validate_func()">
<input type="text" name="course" id="course" onchange="my_validate_func()">
<input type="text" name="center" id="center" onchange="my_validate_func()">
<input type="text" name="roll" id="roll">
<button type="submit">Submit</button>

function my_validate_func (){ 
   if($('#name').val()!="" && $('#phone').val()!="" && $('#course').val()!="" && $('#center').val()!=""){
       $.ajax({
         url:'your_url',
         success: function(response){
            $('#roll').val(response.roll_num);
         }
       });
   }
}

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