How to set current working directory to the directory of the script?
I'm writing a bash script. I need the current working directory to always be the directory that the script is located in.
The default behavior is that the current working directory in the script is that of the shell from which I run it, but I do not want this behavior.
#!/bin/bash
cd "$(dirname "$0")"
The following also works:
cd "${0%/*}"
The syntax is thoroughly described in this StackOverflow answer.
Try the following simple one-liners:
For all UNIX/OSX/Linux
dir=$(cd -P -- "$(dirname -- "$0")" && pwd -P)
Note: A double dash (--) is used in commands to signify the end of command options, so files containing dashes or other special characters won't break the command.
For Linux, Mac and other *BSD:
cd $(dirname $(realpath $0))
With white spaces support:
cd "$(dirname "$(realpath "$0")")";
Note: realpath
should be installed in the most popular Linux distribution by default (like Ubuntu), but in some it can be missing, so you have to install it.
Otherwise you could try something like that (it will use the first existing tool):
cd $(dirname $(readlink -f $0 || realpath $0))
For Linux specific:
cd $(dirname $(readlink -f $0))
Using GNU readlink on *BSD/Mac:
cd $(dirname $(greadlink -f $0))
Note: You need to have coreutils
installed (eg 1. Install Homebrew, 2. brew install coreutils
).
In bash
In bash you can use Parameter Expansions to achieve that, like:
cd ${0%/*}
but it doesn't work if the script is run from the same directory.
Alternatively you can define the following function in bash:
realpath () {
[[ $1 = /* ]] && echo "$1" || echo "$PWD/${1#./}"
}
This function takes 1 argument. If argument has already absolute path, print it as it is, otherwise print $PWD
variable + filename argument (without ./
prefix).
or here is the version taken from Debian .bashrc
file:
function realpath()
{
f=$@
if [ -d "$f" ]; then
base=""
dir="$f"
else
base="/$(basename "$f")"
dir=$(dirname "$f")
fi
dir=$(cd "$dir" && /bin/pwd)
echo "$dir$base"
}
Related:
How to detect the current directory in which I run my shell script?
Getting the source directory of a Bash script from within
Bash script absolute path with OSX
Reliable way for a bash script to get the full path to itself?
See also:
How can I get the behavior of GNU's readlink -f on a Mac?
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