我如何知道Bash脚本中的脚本文件名？

我如何确定脚本本身内的Bash脚本文件的名称？

就像如果我的脚本在文件runme.sh ，那么我将如何让它显示“你正在运行runme.sh”消息而不硬编码？

---

me=`basename "$0"`

对于通常不是你想要的符号链接（你通常不希望用这种方式混淆用户）来说，请尝试：

me="$(basename "$(test -L "$0" && readlink "$0" || echo "$0")")"

国际海事组织，这将产生混乱的输出。 “我跑了foo.sh，但它说我正在运行bar.sh！？必须是一个bug！” 此外，具有不同名称符号链接的目的之一是根据其名称（在某些平台上认为gzip和gunzip）提供不同的功能。

---

# ------------- SCRIPT ------------- #

#!/bin/bash

echo
echo "# arguments called with ---->  ${@}     "
echo "# $1 ---------------------->  $1       "
echo "# $2 ---------------------->  $2       "
echo "# path to me --------------->  ${0}     "
echo "# parent path -------------->  ${0%/*}  "
echo "# my name ------------------>  ${0##*/} "
echo
exit

# ------------- CALLED ------------- #

# Notice on the next line, the first argument is called within double, 
# and single quotes, since it contains two words

$  /misc/shell_scripts/check_root/show_parms.sh "'hello there'" "'william'"

# ------------- RESULTS ------------- #

# arguments called with --->  'hello there' 'william'
# $1 ---------------------->  'hello there'
# $2 ---------------------->  'william'
# path to me -------------->  /misc/shell_scripts/check_root/show_parms.sh
# parent path ------------->  /misc/shell_scripts/check_root
# my name ----------------->  show_parms.sh

# ------------- END ------------- #

---

随着bash> = 3，以下工作：

$ ./s
0 is: ./s
BASH_SOURCE is: ./s
$ . ./s
0 is: bash
BASH_SOURCE is: ./s

$ cat s
#!/bin/bash

printf '$0 is: %sn$BASH_SOURCE is: %sn' "$0" "$BASH_SOURCE"

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