charsets replacements issue

This question already has an answer here:

How to replace all occurrences of a string in JavaScript? 41 answers

---

By default, replace only replaces the first occurrence. To replace all occurrences use a regular expression with the g flag:

function en2fa(str){
    string = string.replace(/1/g, '۱');
    string = string.replace(/2/g, '۲');
    // ...
    return string;
}

var a = '12345';
alert(en2fa(a.replace(/1/g, '3')));

You can make the translation more concise using a lookup table:

var en2faDict = {};
var fa2enDict = {};
"۰۱۲۳۴۵۶۷۸۹".split('').forEach(function(fa, en) {
    en = "" + en;
    en2faDict[en] = fa;
    fa2enDict[fa] = en;
});

function translate(str, dict, pattern) {
    return str.replace(pattern, function(c) { return dict[c]; });
}

function fa2en(str) {
    return translate(str, fa2enDict, /[۰-۹]/g);
}

function en2fa(str) {
    return translate(str, en2faDict, /[0-9]/g);
}

Here is a version which may be faster in some browsers. It uses a for-loop and range checking which relies on the fact that the digits are contiguous:

var en2faDict = {};
var fa2enDict = {};
"۰۱۲۳۴۵۶۷۸۹".split('').forEach(function(fa, en) {
    en = "" + en;
    en2faDict[en] = fa;
    fa2enDict[fa] = en;
});
en2faDict.low = '0'.charCodeAt(0);
en2faDict.high = '9'.charCodeAt(0);
fa2enDict.low = en2faDict['0'].charCodeAt(0);
fa2enDict.high = en2faDict['9'].charCodeAt(0);

function translate(str, dict) {
    var i, l = str.length, result = "";
    for (i = 0; i < l; i++) {
        if (str.charCodeAt(i) >= dict.low && str.charCodeAt(i) <= dict.high)
            result += dict[str[i]];
        else
            result += str[i];
    }
    return result;
}

function fa2en(str) {
    return translate(str, fa2enDict);
}

function en2fa(str) {
    return translate(str, en2faDict);
}

---

From clues in your question, Your issue is in the way you are doing the replace. You showed us fa2en , I presume your en2fa is similar. However a better and working implementation would be as follows :

  function en2fa (str) {
    return str.replace (/d/g, function (d) {
      return '۰۱۲۳۴۵۶۷۸۹'.charAt (+d);
    });
  }

You main problem was as described by @tom in your code using string replacement only replaces the first occurrence. @tom 's answer while it might work is not standard. To replace all occurrences you should use a regExp replace with a g modifier. This results in significantly shorter code also !

链接地址: http://www.djcxy.com/p/16846.html

上一篇: 如何用replace替换创建一个“bbcode”javascript

下一篇: charsets替换问题