Python CodeLab词典
这个问题在这里已经有了答案：
你可能需要使用defaultdict - 这里nafta被用作三个关键字（ canadian_capitals, mexican_capitals, us_capitals ），如下所示 -
>>>dic = defaultdict(list)
>>>lst = ['nafta1', 'canadian_capitals1', 'mexican_capitals1', 'us_capitals1', 'nafta2', 'canadian_capitals2', 'mexican_capitals2', 'us_capitals2']
>>>grouped_lst = [lst[i:i+4] for i in range(0,len(lst),4)]
>>>[['nafta1', 'canadian_capitals1', 'mexican_capitals1', 'us_capitals1'], ['nafta2', 'canadian_capitals2', 'mexican_capitals2', 'us_capitals2']]
>>>for i in grouped_lst:dic[i[0]]=i[1:]
>>>dic.items()
>>>[('nafta1', ['canadian_capitals1', 'mexican_capitals1', 'us_capitals1']), ('nafta2', ['canadian_capitals2', 'mexican_capitals2', 'us_capitals2'])]
>>>for i in dic.keys():print dic[i]
>>>['canadian_capitals1', 'mexican_capitals1', 'us_capitals1']
['canadian_capitals2', 'mexican_capitals2', 'us_capitals2']