Sort Python dict by datetime value

 

This question already has an answer here:

  • How do I sort a dictionary by value? 38 answers

    • You could sort the keys like this: 

    sorted(dct, key=dct.get)

    See the Sorting Mini-HOW TO for an explanation of this and other techniques for sorting.

    Bearing in mind that the question asks how to sort by the datetime values, here's a possible answer: 

    sorted(dct.items(), key=lambda p: p[1], reverse=True)

=> [('raspberry', datetime.datetime(2013, 1, 9, 0, 0)),
    ('apple', datetime.datetime(2012, 12, 20, 0, 0)),
    ('orange', datetime.datetime(2012, 2, 4, 0, 0))]

    If you're only interested in the keys: 

    [k for k, v in sorted(dct.items(), key=lambda p: p[1], reverse=True)]

=> ['raspberry', 'apple', 'orange']

    这很简单，你只需要做，就像： 

     from operator import itemgetter
 sorted(a.items(),key=itemgetter(1),reverse=True)
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