sort list by frequency

This question already has an answer here:

How do I sort a dictionary by value? 38 answers

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You've to use word_freq.items() here:

lis = sorted(word_freq.items(), key = lambda x:x[1], reverse = True)
for word,freq in lis:
    print ("%-10s %d" % (word, freq))

Don't use list as a variable name.

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使用collections.Counter来帮助计算事物，并with语句来帮助打开（和关闭）文件。

import collections

with open('C:TempTest2.txt', 'r') as f:
    text = f.read()

word_freq = collections.Counter(text.lower().split())
for word, freq in word_freq.most_common():
    print ("%-10s %d" % (word, freq))

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看看collections.Counter

>>> wordlist = ['foo', 'bar', 'foo', 'baz']
>>> import collections
>>> counter = collections.Counter(wordlist)
>>> counter.most_common()
[('foo', 2), ('baz', 1), ('bar', 1)]

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