removing item from array after match

This question already has an answer here:

How do I remove a particular element from an array in JavaScript? 63 answers

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试试这可能对你有帮助

function arr_diff(a1, a2)
{
  var a=[], diff=[];
  for(var i=0;i<a1.length;i++)
    a[a1[i]]=true;
  for(var i=0;i<a2.length;i++)
    if(a[a2[i]]) delete a[a2[i]];
    else a[a2[i]]=true;
  for(var k in a)
    diff.push(k);
  return diff;
}
var a = [1,2,3,4,5,6]
var b = [2,3]
console.log(arr_diff(a,b));

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There are several errors here. First of all, jQuery's inArray searches for elements, not subArrays. So you might conceivably imagine that you would find that

$.inArray([2, 3], [[1, 2], [2, 3], [3, 4], [4, 5]])

would yield 1 , but in fact even that won't work, because it follows the Array.prototype standards and compares with reference equality.

It certainly won't find the array [2, 3] as an element of [1, 2, 3, 4, 5] .

Next, if it did happen to find that array, Array.prototype has no remove function.

You might want to look at Array.prototype.splice() .

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Here is one option ( arraysEqual() borrowed from this answer):

function arraysEqual(a, b) {
    if (a === b) return true;
    if (a == null || b == null) return false;
    if (a.length != b.length) return false;

    for (var i = 0; i < a.length; ++i) {
        if (a[i] !== b[i]) return false;
    }
    return true;
}

for (var i = 0; i <= a.length - b.length; i++) {
    var slice = a.slice(i, i + b.length);
    if (arraysEqual(slice, b)) {
        a.splice(i, b.length);
    }
}

This loops through a comparing slices of a to b , and removing that slice when a match is found.

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