How do I sort a list of dictionaries by values of the dictionary in Python?
I got a list of dictionaries and want that to be sorted by a value of that dictionary.
This
[{'name':'Homer', 'age':39}, {'name':'Bart', 'age':10}]
sorted by name, should become
[{'name':'Bart', 'age':10}, {'name':'Homer', 'age':39}]
It may look cleaner using a key instead a cmp:
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
or as JFSebastian and others suggested,
from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))
For completeness (as pointed out in comments by fitzgeraldsteele), add reverse=True to sort descending
newlist = sorted(l, key=itemgetter('name'), reverse=True)
import operator
To sort the list of dictionaries by key='name':
list_of_dicts.sort(key=operator.itemgetter('name'))
To sort the list of dictionaries by key='age':
list_of_dicts.sort(key=operator.itemgetter('age'))
If you want to sort the list by multiple keys you can do the following:
my_list = [{'name':'Homer', 'age':39}, {'name':'Milhouse', 'age':10}, {'name':'Bart', 'age':10} ]
sortedlist = sorted(my_list , key=lambda elem: "%02d %s" % (elem['age'], elem['name']))
It is rather hackish, since it relies on converting the values into a single string representation for comparison, but it works as expected for numbers including negative ones (although you will need to format your string appropriately with zero paddings if you are using numbers)
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