Sorting on a custom order

This question already has an answer here:

Sort array of objects by string property value in JavaScript 33 answers

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Cerbrus代码的改进版本：

var ordering = {}, // map for efficient lookup of sortIndex
    sortOrder = ['fruit','candy','vegetable'];
for (var i=0; i<sortOrder.length; i++)
    ordering[sortOrder[i]] = i;

somethingToSort.sort( function(a, b) {
    return (ordering[a.type] - ordering[b.type]) || a.name.localeCompare(b.name);
});

---

Try this:

var sortOrder = ['fruit','candy','vegetable'];   // Declare a array that defines the order of the elements to be sorted.
somethingToSort.sort(
    function(a, b){                              // Pass a function to the sort that takes 2 elements to compare
        if(a.type == b.type){                    // If the elements both have the same `type`,
            return a.name.localeCompare(b.name); // Compare the elements by `name`.
        }else{                                   // Otherwise,
            return sortOrder.indexOf(a.type) - sortOrder.indexOf(b.type); // Substract indexes, If element `a` comes first in the array, the returned value will be negative, resulting in it being sorted before `b`, and vice versa.
        }
    }
);

Also, your object declaration is incorrect. Instead of:

{
    type = "fruit",
    name = "banana"
}, // etc

Use:

{
    type: "fruit",
    name: "banana"
}, // etc

So, replace the = signs with : 's.

---

Array.sort接受一个排序函数，您可以在其中应用自定义排序逻辑。

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