javascript sort and sort equals on result. how?

This question already has an answer here:

Sort array of objects by string property value in JavaScript 33 answers

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为了让你排序稳定，你需要比较“相等”项目的索引：

// mass = [{name:…, count:…}, {name:…, count:…}, …]
for (var i=0; i<mass.length; i++)
    mass[i].index = i;
mass.sort(function(a, b) {
    return compareElements(a, b) || a.index - b.index;
});
function compareElements(a, b) {
    // something
    return a.count - b.count;
}

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If your objects are like:

var arrObj = {
   name: "aaa",
   count: 1
};

Use this function for comparing:

function compareElements(a, b)
{
  return a.count - b.count;
}

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