如何在特定模式之上和之下的线条进行grep
我想搜索特定图案(比如小节线),而且打印的上方和下方(即1线)的图案或2行上方和下方的图案线条。
Foo line
Bar line
Baz line
....
Foo1 line
Bar line
Baz1 line
....
使用带参数-A
和-B
grep
指示要在您的模式周围打印的线A
fter和B
之前的数量a:
grep -A1 -B1 yourpattern file
An
代表n
“后”匹配线。 Bm
代表比赛前的m
条线。 如果两个数字都相同,只需使用-C
:
grep -C1 yourpattern file
测试
$ cat file
Foo line
Bar line
Baz line
hello
bye
hello
Foo1 line
Bar line
Baz1 line
让我们grep
:
$ grep -A1 -B1 Bar file
Foo line
Bar line
Baz line
--
Foo1 line
Bar line
Baz1 line
要摆脱组分隔符,可以使用--no-group-separator
:
$ grep --no-group-separator -A1 -B1 Bar file
Foo line
Bar line
Baz line
Foo1 line
Bar line
Baz1 line
从man grep
:
-A NUM, --after-context=NUM
Print NUM lines of trailing context after matching lines.
Places a line containing a group separator (--) between
contiguous groups of matches. With the -o or --only-matching
option, this has no effect and a warning is given.
-B NUM, --before-context=NUM
Print NUM lines of leading context before matching lines.
Places a line containing a group separator (--) between
contiguous groups of matches. With the -o or --only-matching
option, this has no effect and a warning is given.
-C NUM, -NUM, --context=NUM
Print NUM lines of output context. Places a line containing a
group separator (--) between contiguous groups of matches. With
the -o or --only-matching option, this has no effect and a
warning is given.
grep
是你的工具,但它可以用awk
完成
awk '{a[NR]=$0} $0~s {f=NR} END {for (i=f-B;i<=f+A;i++) print a[i]}' B=1 A=2 s="Bar" file
注意,这也会发现一个命中。
或者用grep
grep -A2 -B1 "Bar" file
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