Meaning of "+ +" operator (not ++)

 

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    • There is no + + operator. There's a + operator (which occurs in both unary and binary forms), and a ++ operator, not used here.

    Each of those is a binary + operator followed by one or more unary + operators.

    This: 

    c = c + + "d";

    is equivalent to 

    c = c + (+ "d");

    This: 

    c = c + + + "d";

    is equivalent to: 

    c = c + (+ + "d");

    or: 

    c = c + (+ (+ "d"));

    And so forth.

    The first + is a binary plus which calculates the sum of c and the second term.

    The remaining + are unary plus operators. In + "d" , "d" is of type const char[2] , and decays to const char* . Then + is applied to the pointer which has no effect, and returns the same const char* .

    c + + + "d" is equivalent to c + (+(+"d")) .

    这只是很多一元加号。

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