javascript if statement if url contains substring
You can use the indexOf method
// Function is used to determine whether a string contains another string
function contains(search, find) {
///<summary>Sees if a string contains another string</summary>
///<param type="string" name="search">The string to search in</param>
///<param type="string" name="find">The string to find</param>
///<returns type="bool">A boolean value indicating whether the search string contained the find string</returns>
return search.indexOf(find) !== -1;
}
Here's some sample usage:
var url = document.URL;
var substring = 'foo';
if (contains(url.toLowerCase(), substring.toLowerCase()) {
// Contains string
}
The contains function is case sentitive , however; as demonstrated in my example, you can make it incasesensitive by calling the StringPrototype.toLowerCase Method
例如，您可以使用indexOf：
if (url.indexOf(substring)>=0) {
This is a forward-looking answer, and won't work in current implementations.
ECMAScript 6 is currently defining a String.prototype.contains method. This will allow you to do:
if (url.contains(substring)) {
Again, this is a future addition. Currently ECMAScript 6 (Harmony) is being drafted, and this could technically be removed, though it doesn't seem likely.
Current draft:
15.5.4.24 String.prototype.contains (searchString, position = 0 )
The contains method takes two arguments, searchString and position, and performs the following steps:
O be CheckObjectCoercible(this value) . S be ToString(O) . ReturnIfAbrupt(S) . searchStr be ToString(searchString) . ReturnIfAbrupt(searchStr) . pos be ToInteger(position) . (If position is undefined , this step produces the value 0 ). ReturnIfAbrupt(pos) . len be the number of elements in S . start be min(max(pos, 0), len) . searchLen be the number of characters in searchStr . k not smaller than start such that k + searchLen is not greater than len , and for all nonnegative integers j less than searchLen , the character at position k+j of S is the same as the character at position j of searchStr , return true ; but if there is no such integer k , return false . 上一篇: 如何使用JavaScript验证“包含”