Incrementing integer variable of global scope in Python

2018-06-06 17:43:33

This question already has an answer here:

How do I pass a variable by reference? 23 answers

Because x is a local (all function arguments are), not a global, and integers are not mutable.

So x += 1 is the same as x = x + 1 , producing a new integer object, and x is rebound to that.

You can mark x a global in the function:

def add_one():
    global x
    x += 1

There is no point in passing in x as an argument here.

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