How do I pass a JSONObject from Android application to a PHP file?
I want to send a simple JSON object to PHP server,but when i try to retrieve that object on the server side,there is nothing i mean my $_POST variable is empty. The server side is PHP 5.2 and I'm using android emulator 10...Could someone have a look on my code and tell me what is going wrong? Thanks a lot
public void uploadJSon() throws ClientProtocolException, IOException, JSONException{
HttpClient httpclient = new DefaultHttpClient();
String url = "http://so-dev-deb.niv2.com/suivi_activite/test.php";
HttpPost httppost = new HttpPost(url);
JSONObject json = new JSONObject();
json.put("username", "bob");
json.put("email", "test@testsite.com");
List nvps = new ArrayList ();
nvps.add(new BasicNameValuePair("value", json.toString()));
httppost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
URL test_url = new URL(url);
URLConnection connection = test_url.openConnection();
connection.setDoOutput(true);
HttpResponse response;
response = httpclient.execute(httppost);
Log.i("NVPS",nvps.get(0).toString());
Log.i("JSON",json.toString());
Log.i("response", response.getEntity().getContent().toString());
Log.i("response status",response.getStatusLine().toString());
BufferedReader in = new BufferedReader(
new InputStreamReader(
connection.getInputStream()));
String decodedString;
while ((decodedString = in.readLine()) != null) {
//System.out.println(decodedString);
Log.i("info 10",decodedString);
}
in.close();
}
The server side test.php is :
<?php
$tmp = json_decode($_POST['value']);
var_dump($tmp);
?>
我通常采用这种方法在Java代码中生成JSON对象：
StringWriter writer = new StringWriter();
JSONWriter jsonWriter = new JSONWriter(writer);
jsonWriter.object();
jsonWriter.key("key1").value("test1");
jsonWriter.key("key2").value("test2");
jsonWriter.endObject();
String toSend = writer.toString();
I'm no expert in PHP, However, a project I worked on decoded the json that I submitted like this.
$jsonData = file_get_contents("php://input");
if(isset($jsonData) && !empty($jsonData)) { $this->data = json_decode($jsonData,true); }
public static String login(Context context, String email, String pwd) {
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); // Timeout
// Limit
HttpResponse response;
JSONObject json = new JSONObject();
try {
Log.d("Debug","Login Url:" + context.getResources().getString(
R.string.url) + context.getResources().getString(
R.string.login));
HttpPost post = new HttpPost(context.getResources().getString(
R.string.url) + context.getResources().getString(
R.string.login));
post.setHeader("Accept", "application/json");
post.setHeader("Content-type", "application/json");
json.put("email", email);
json.put("password", pwd);
StringEntity se = new StringEntity("{"User":" + json.toString()
+ "}");
post.setEntity(se);
response = client.execute(post);
if (response != null) {
json = getResult(response);
if(statusOK(json)){
return new String(json.getString("token"));
}
}
} catch (Exception e) {
Log.e("Error", "Error Login", e);
}
// printJSON(json);
return "ERROR";
}
注意我将JSON包装在用户中，因为服务器需要这个用于我的情况。
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