Java读取数据POST内容
我有一个API，我正在测试。 API接收POST请求并像这样读取它
StringBuffer jb = new StringBuffer();
String line = null;
try {
BufferedReader reader = request.getReader();
while ((line = reader.readLine()) != null)
jb.append(line);
System.out.println("jb: "+jb);
System.out.println("request.getHeader('content-type'): "+request.getHeader("content-type"));
} catch (Exception e) { /*report an error*/ }
当我在“application / json; charset = utf-8”中发送POST请求时，
httpPost.setHeader("content-type", "application/json;charset=utf-8");
它打印这个：
jb: {"client_domain":"=....); //proper Json data
request.getHeader('content-type'): application/json;charset=utf-8
我可以正确读取数据。
然而，我的问题是，当我发送数据的方式相同，但我设置了内容类型“application / x-www-form-urlencoded; charset = utf-8”
httpPost.setHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
测试是相同的，只是内容类型不同，但似乎我没有收到任何数据了：
jb:
request.getHeader('content-type'): application/x-www-form-urlencoded;charset=utf-8
任何想法？
///更新
这是Spring控制器
@RequestMapping(value = {"user/add"}, method = RequestMethod.POST, produces="application/json; charset=utf-8")
@ResponseBody
public ResponseEntity<String> getNewUserApi(HttpServletRequest request,
HttpServletResponse response) throws Exception {
Map<String, Object> jsonObj = new HashMap<String, Object>();
StringBuffer jb = new StringBuffer();
String line = null;
try {
BufferedReader reader = request.getReader();
while ((line = reader.readLine()) != null)
jb.append(line);
System.out.println("jb: "+jb);
System.out.println("request.getHeader('content-type'): "+request.getHeader("content-type"));
} catch (Exception e) { /*report an error*/ }
///I create my JSon that will be sent back
return JsonUtils.createJson(jsonObj);
//更新2这是我如何发送数据
public static void main(String[] args) throws Exception {
String url = "http://localhost:8080/child/apiv1/user/add";
CloseableHttpClient client = HttpClientBuilder.create().build();
HttpPost httpPost = new HttpPost(url);
httpPost.setHeader("content-type", "application/x-www-form-urlencoded;charset=utf-8");
try {
//we had to the parameters to the post request
JSONObject json = new JSONObject();
json.put("client_id", "fashfksajfhjsakfaskljhflakj");
json.put("client_secret", "9435798243750923470925709348509275092");
json.put("client_domain", "dummy.localhost.com");
//create the user json object
JSONObject userObj = new JSONObject();
userObj.put("email", "johnsmith42@yopmail.com");
userObj.put("name", "Anna Sax");
JSONArray childrenArray = new JSONArray();
JSONObject child1 = new JSONObject();
child1.put("name", "Iphone 6");
child1.put("age", "2");
childrenArray.put(child1);
userObj.put("children", childrenArray);
json.put("user", childObj);
StringEntity params = new StringEntity(json.toString());
httpPost.setEntity(params);
System.out.println("executing request: " + httpPost.getRequestLine());
HttpResponse response;
response = client.execute(httpPost);
//[...]
} //End main
我知道创建Json并将其发送到“application / x-www-form-urlencoded”并没有什么意义，但这只是我们的用户无法解决他的问题，它只会发送“应用程序/的X WWW窗体-urlencoded”。
@RequestMapping的'produce'属性表明客户端只能接受application / json数据，因此您可以将其删除或将其更改为'application / x-www-form-urlencoded'。
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