c++
I'm trying to switch between an explicit and an implicit conversion constructor via enable_if .
My code currently looks like
#include <type_traits>
#include <cstdint>
enum class enabled {};
template <bool B, typename T = void> using enable_if_t = typename std::enable_if<B, T>::type;
template <bool B, typename T = void> using disable_if_t = typename std::enable_if<!B, T>::type;
template <std::intmax_t A> struct SStruct
{
static constexpr std::intmax_t a = A;
};
template <typename T> struct SCheckEnable : std::integral_constant<bool, T::a == 0>
{
};
template <typename U, typename T> class CClass
{
public:
template <typename T2, enable_if_t<SCheckEnable<U>::value, enabled>...> constexpr CClass(T2 v) : val(v) {};
template <typename T2, disable_if_t<SCheckEnable<U>::value, enabled>...> explicit constexpr CClass(T2 v) : val(v) {};
private:
T val;
};
int main()
{
CClass<SStruct<0>, double> a = 1; // should use implicit constructor
CClass<SStruct<1>, double> b = CClass<SStruct<1>, double>(1); // should use explicit constructor
}
The true in the enable_if s is dependent of the template parameter U
If I try to compile this minimal example with g++ 4.9.1 and --std=c++11 enabled I get the following errors
sfinae.cpp: In substitution of ‘template<bool B, class T> using disable_if_t = typename std::enable_if<(! B), T>::type [with bool B = true; T = enabled]’:
sfinae.cpp:13:52: required from here
sfinae.cpp:7:95: error: no type named ‘type’ in ‘struct std::enable_if<false, enabled>’
template <bool B, typename T = void> using disable_if_t = typename std::enable_if<!B, T>::type;
^
sfinae.cpp:19:68: error: prototype for ‘constexpr CClass<U, T>::CClass(T2)’ does not match any in class ‘CClass<U, T>’
template <typename U, typename T> template <typename T2> constexpr CClass<U, T>::CClass(T2 v) : val(v)
^
sfinae.cpp:13:77: error: candidates are: template<class U, class T> template<class T2, int ...<anonymous> > constexpr CClass<U, T>::CClass(T2)
template <typename T2, disable_if_t<true, enabled>...> explicit constexpr CClass(T2 v);
^
sfinae.cpp:12:67: error: template<class U, class T> template<class T2, enabled ...<anonymous> > constexpr CClass<U, T>::CClass(T2)
template <typename T2, enable_if_t<true, enabled>...> constexpr CClass(T2 v);
^
Any idea how to select between explicit and implicit construction based on parameter U here?
Use
template <class...> struct null_v : std::integral_constant<int, 0> {};
and define the constructors as
template <typename T2,
long = null_v<enable_if_t<SCheckEnable<U>::value, T2>>::value>
constexpr CClass(T2 v) : val(v) {};
template <typename T2,
int = null_v<disable_if_t<SCheckEnable<U>::value, T2>>::value>
explicit constexpr CClass(T2 v) : val(v) {};
Making the argument dependent and actually instantiated. Demo .
[temp.deduct]/8:
If a substitution results in an invalid type or expression, type deduction fails. An invalid type or expression is one that would be ill-formed if written using the substituted arguments .
In your case the error occurs outside of any substitution, so that's not causing a deduction failure but rather makes your code ill-formed.
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