JQuery: if div is visible
This question already has an answer here:
You can use .is(':visible')
Selects all elements that are visible.
For example:
if($('#selectDiv').is(':visible')){
Also, you can get the div which is visible by:
$('div:visible').callYourFunction();
Live example:
console.log($('#selectDiv').is(':visible'));
console.log($('#visibleDiv').is(':visible'));
#selectDiv {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="selectDiv"></div>
<div id="visibleDiv"></div>
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