Set environment variables from file
I'm writing a script in bash which parses files with 3 variables in a certain folder, this is one of them:
MINIENTREGA_FECHALIMITE="2011-03-31"
MINIENTREGA_FICHEROS="informe.txt programa.c"
MINIENTREGA_DESTINO="./destino/entrega-prac1"
This file is stored in ./conf/prac1
My script minientrega.sh then parses the file using this code:
cat ./conf/$1 | while read line; do
export $line
done
But when I execute minientrega.sh prac1 in the command line it doesn't set the environment variables
I also tried using source ./conf/$1 but the same problem still applies
Maybe there is some other way to do this, I just need to use the environment variables of the file I pass as the argument of my script.
Problem with your approach is the export in the while loop is happening in a sub shell, and those variable will not be available in current shell (parent shell of while loop).
Add export command in the file itself:
export MINIENTREGA_FECHALIMITE="2011-03-31"
export MINIENTREGA_FICHEROS="informe.txt programa.c"
export MINIENTREGA_DESTINO="./destino/entrega-prac1"
Then you need to source in the file in current shell using:
. ./conf/prac1
OR
source ./conf/prac1
This might be helpful:
export $(cat .env | xargs) && rails c
Reason why I use this is if I want to test .env stuff in my rails console.
gabrielf came up with a good way to keep the variables local. This solves the potential problem when going from project to project.
env $(cat .env | xargs) rails
I've tested this with bash 3.2.51(1)-release
Update: To ignore lines that start with # , use this (thanks to Pete's comment):
export $(cat .env | grep -v ^# | xargs)
And if you want to unset all of the variables defined in the file, use this:
unset $(cat .env | grep -v ^# | sed -E 's/(.*)=.*/1/' | xargs)
-o allexport enables all following variable definitions to be exported. +o allexport disables this feature.
set -o allexport
source conf-file
set +o allexport
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