JavaScript object pushed into an array
Possible Duplicate:
How do I correctly clone a JavaScript object?
I have this code:
var temp = [];
var obj = {name:"1"};
temp.push(obj);
obj.name = "2";
temp.push(obj);
What I'm expecting to be true:
temp[0].name == "1" && temp[1].name == "2";
What actually happens:
temp[0].name == "2" && temp[1].name == "2";
Why does this happen, and how I can get what I'm expecting?
JavaScript arrays hold references to objects, rather than objects themselves. When you push an object into the array it does not create a new object, but it simply puts a reference to the object, that obj also points to, into the array.
So in the end obj, temp[0], and temp1 all point to the same object. To actually create a completely new object, you can use Object.create() or jQuery.extend({},obj). Though in your case it's easy enough just to create a new simple object using var newobj = {name="2"}
JavaScript objects are passed by reference. In your case you have only one object "obj", and temp[0] and temp[1] are pointing to the same object.
obj是一个对象在数组中添加引用，所以你实际上添加了相同的obj两次。
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