How to find the largest file in a directory and its subdirectories?

We're just starting a UNIX class and are learning a variety of Bash commands. Our assignment involves performing various commands on a directory that has a number of folders under it as well.

I know how to list and count all the regular files from the root folder using:

find . -type l | wc -l

But I'd like to know where to go from there in order to find the largest file in the whole directory. I've seen somethings regarding a du command, but we haven't learned that, so in the repertoire of things we've learned I assume we need to somehow connect it to the ls -t command.

And pardon me if my 'lingo' isn't correct, I'm still getting used to it!


Quote from this link-

If you want to find and print the top 10 largest files names (not directories) in a particular directory and its sub directories

$ find . -printf '%s %pn'|sort -nr|head

To restrict the search to the present directory use "-maxdepth 1" with find.

$ find . -maxdepth 1 -printf '%s %pn'|sort -nr|head

And to print the top 10 largest "files and directories":

$ du -a . | sort -nr | head

** Use "head -n X" instead of the only "head" above to print the top X largest files (in all the above examples)


To find the top 25 files in the current directory and its subdirectories:

find . -type f -exec ls -al {} ; | sort -nr -k5 | head -n 25

This will output the top 25 files by sorting based on the size of the files via the "sort -nr -k5" piped command.


find . -type f | xargs ls -lS | head -n 1

outputs

-rw-r--r--  1 nneonneo  staff  9274991 Apr 11 02:29 ./devel/misc/test.out

If you just want the filename:

find . -type f | xargs ls -1S | head -n 1

This avoids using awk and allows you to use whatever flags you want in ls .

Caveat. Because xargs tries to avoid building overlong command lines, this might fail if you run it on a directory with a lot of files because ls ends up executing more than once. It's not an insurmountable problem (you can collect the head -n 1 output from each ls invocation, and run ls -S again, looping until you have a single file), but it does mar this approach somewhat.

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