bash选择菜单获取索引
例
#!/bin/bash
INSTALL_PATH="/usr/local"
BFGMINER_INSTALL_PATH="${INSTALL_PATH}/bfgminer"
BFGMINER_REPO="https://github.com/luke-jr/bfgminer.git"
list_last_ten_bfgminer_tags () {
cd ${BFGMINER_INSTALL_PATH}
git for-each-ref --format="%(refname)" --sort=-taggerdate --count=10 refs/tags | cut -c 6-
}
clone_bfgminer () {
cd ${INSTALL_PATH}
git clone ${BFGMINER_REPO} ${BFGMINER_INSTALL_PATH}
}
echo "select number to switch tag or n to continue"
select result in master $(list_last_ten_bfgminer_tags)
do
# HOW DO I CHECK THE INDEX??????? <================================= QUESTION
if [[ ${result} == [0-9] && ${result} < 11 && ${result} > 0 ]]
then
echo "switching to tag ${result}"
cd ${BFGMINER_INSTALL_PATH}
git checkout ${result}
else
echo "continue installing master"
fi
break
done
因此，如果用户输入1，case语句会检查文本上的匹配，我如何才能匹配1？
您不需要检查选择了哪个值; 你可以简单地使用它。 你唯一想检查的是master ，这很容易做到。
select result in master $(list_last_ten_bfgminer_tags)
do
if [[ $result = master ]]; then
echo "continue installing master"
elif [[ -z "$result" ]]; then
continue
else
echo "switching to tag ${result}"
cd ${BFGMINER_INSTALL_PATH}
git checkout ${result}
fi
break
done
使用$REPLY变量
PS3="Select what you want>"
select answer in "aaa" "bbb" "ccc" "exit program"
do
case "$REPLY" in
1) echo "1" ; break;;
2) echo "2" ; break;;
3) echo "3" ; break;;
4) exit ;;
esac
done
我很努力地理解你的问题，但这里是一些示例代码; 该数组可以动态填充，我猜你是从哪里来的：
$ cat t.sh
#!/bin/bash
foo=(one two three four)
echo "Please select an option: "
select reply in "${foo[@]}"; do
[ -n "${reply}" ] && break
done
echo "You selected: ${reply}"
。
$ ./t.sh
Please select an option:
1) one
2) two
3) three
4) four
#? 5
#? 100
#? 2
You selected: two
这是如何不足？
当然，如果您希望输出/逻辑与select不同，您也可以使用自己的read和构建功能。