如何获取用户输入并检查数组中的项目？
我希望用户输入他们的胡须风格，然后我将它与一系列胡须样式的胡须进行核对。 这是我想做的额外事情，我不知道如何解决。 我接触到的唯一项目是（包括？），但我想要：
（数组名称）.include？ （从用户输入的值）
require_relative 'list_of'
require_relative 'error'
#User inputs a value
def get_beard
puts "What style of beard do you have?"
beard = gets
if check_beard_ok?(beard)
then no_problem(beard) end
end
#Value passed to check length doesn't exceed 25 letters
def check_beard_ok?(beard)
# while beard.length < 25
# beard.in?(beard_style)
# end
end
#The value is printed here without any errors occuring
def no_problem(beard)
puts "nYou have a " + beard
puts "nThere are other beards that you could try like..."
list_of
end
get_beard
看看这个http://www.ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F
你可以做
breads = [ "Banana bread", "Beer bread", "Pumpernickel" ]
breads_selected = [ "Banana bread"]
if breads.include?(breads_selected)
# this is true
end
unless breads.include?(breads_selected)
# this is false
end
beards = ['long','short','ginger','dirty']
selected = ['ginger']
selected - beards
=> []
（选定的胡须）将从胡须中不存在的所选元素中返回元素。 生姜在列表中，所以我们得到一个空阵列。
beards = ['long','short','ginger','dirty']
selected = ['ginger', 'fluffy']
selected - beards
=> 'fluffy'
我的第二个例子返回蓬松，因为它不在列表中。 你可以将它封装在自己的方法中，检查返回的数组是否为空。
这种方法非常棒，因为您不仅可以检查所选元素是否存在，还会返回那些不存在的元素，如果您想要返回某种有意义的错误，这会很有帮助。
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