how to send a url using Javascript ajax?
Possible Duplicate:
How to encode a URL in JavaScript?
I am trying to send a url using the following code to a php code, but as the url include &a=12&b=4 once I get the value of the "a" variable in my php code the last part of address is removed.
url = http://www.example.com/help.jpg?x=10&a=12&b=4 but the url that I get in my php file is http://www.example.com/help.jpg?x=10 (&a=12&b=4 is removed, I know the reason is that javascript,ajax mix it up with the url address and do not know its just a value but do not know how to solve it)
function upload(url){
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("output").innerHTML= xmlhttp.responseText;
}
}
xmlhttp.open("GET","Photos.php?a="+url,true);
xmlhttp.send();
}
if(isset($_GET["a"]))
{
$Address = $_GET["a"];
echo $Address;
}
output is >>> " http://www.example.com/help.jpg?x=10" but it should be http://www.example.com/help.jpg?x=10&a=12&b=4
您需要对参数进行编码
xmlhttp.open("GET","Photos.php?a="+encodeURIComponent(url),true);
You need to encode the URL. You can use encodeURIComponent(str) and encodeURI(str) like:
var eurl = encodeURIComponent("http://www.example.com/help.jpg?x=10&a=12&b=4");
xmlhttp.open("GET","Photos.php?a=" + eurl, true);
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