JSON复制到JSON基于密钥复制
这个问题在这里已经有了答案：
如果你不使用jquery，按如下操作：
function parseandmatchjson(json1, json2) {
var combined_json = {};
// Deep copy of json1 object literal
for (var key in json1) {
combined_json[key] = json1[key];
}
// Copy other values from json2
for (var key in json2) {
if (! json1.hasOwnProperty(key))
combined_json[key] = json2[key];
}
return combined_json;
}
var json1 = {val1: 1, val2:2, val3:3};
var json2 = {val1: 52, val2:56, val7: 7, val5: 5, val3:33};
var json3 = parseandmatchjson(json1, json2);
如果你正在使用jQuery，那就更简单了
var json1 = {val1: 1, val2:2, val3:3};
var json2 = {val1: 52, val2:56, val7: 7, val5: 5, val3:33};
var json3 = $.extend({}, json2, json1);
编辑
基于采购订单的更新问题，这里是其更新的解决方案，以涵盖嵌套文字的情况
FYA，在下一个解决方案中，我假设你不使用jQuery，因为你没有在你的问题中指定这个
function parseandmatchjson(json1, json2) {
// private function to traverse json objects recursively
function traverse(object, callback) {
for (var key in object) {
// only return leaf nodes
if((/boolean|number|string/).test(typeof object[key]))
callback.apply(this, [object, key, object[key]]);
// if not base condition, dig deeper in recursion
if (object[key] !== null && typeof(object[key]) == "object")
traverse(object[key], callback);
}
}
// create deep clone copy of json1
var result = JSON.parse(JSON.stringify(json1));
// create a flattened version of json2 for doing optimized lookups
var flat_json2 = {};
traverse(json2, function(object, key,value) {
flat_json2[key] = value;
});
// overwrite values in results, if they exist in json2
traverse(result, function(object, key, value) {
if(typeof flat_json2[key] !== "undefined" )
object[key] = flat_json2[key];
});
return result;
}
// Now, lets test it
var json1 = {wrapper: {val1: 1, val2: 2}}
var json2 = {val1: 'without wrapper'}
var merged_json = parseandmatchjson(json1, json2);
// check the result with a simple alert
alert(JSON.stringify(merged_json));
这里是一个JSFiddle Sample点击这里
链接地址: http://www.djcxy.com/p/27339.html