"if not in" in python to get the index

This question already has an answer here:

Finding the index of an item given a list containing it in Python 23 answers

---

>>> a=[2,3,4]
>>> a.index(3)
1

编辑

>>> a=[2,3,4]
>>> def check(n):
...     try:
...             print a.index(n)
...     except ValueError:
...             print "Element not found in list a"
... 
>>> check(5)
Element not found in list a
>>> check(3)
1

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