if a is not an element in a list how to print?

This question already has an answer here:

Finding the index of an item given a list containing it in Python 23 answers

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I think your looking something like the below example

my_list = [1, 3, 5]
number = input("Choose a number from 1 to 5: ")
if int(number) in my_list:
    print("error. . . . ")
else:
    print(int(number))

And when you run it this is how it works

Choose a number from 1 to 5: 2

2

Choose a number from 1 to 5: 1

error. . . .

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首先，您需要将用户输入视为int ，然后检查用户输入的数字是否存在于my_list 。

my_list = [1, 3, 5]
number = int(input("Choose a number from 1 to 5: "))


if number in my_list:
  print('Error')
else:
  print(number)

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