PHP是否有结构或枚举，如果不是什么是他们最好的实现？
这个问题在这里已经有了答案：
我实际上为PHP创建了自己的枚举类型，对于我需要做的事情，它工作得很好。 没有typedefs但很好：D
函数枚举（$ array，$ asBitwise = false）
/*
* I formed another version that includes typedefs
* but seeing how this hacky is not viewed as compliant
* with programming standards I won't post it unless someone
* wishes to request. I use this a lot to save me the hassle of manually
* defining bitwise constants, but if you feel it is too pointless
* for you I can understand. Not trying to reinvent the wheel here
*
*/
function enum($array, $asBitwise = false) {
if(!is_array($array) or count($array) < 1) return false; // Error incorrect type
$n = 0; // Counter variable
foreach($array as $i) {
if($i === null) {
if($n == 0) {
if(!define($i, 0)) return false;
} else
if(!define($i, $asBitwise ? 1 << ($n - 1) : $n)) return false;
} $n++;
} return true; // Successfully defined all variables
}
用法（示例）：
enum(array(
'BrowserTypeUnknown', // 0
'BrowserTypeIE', // 1
'BrowserTypeNetscape', // 2
'BrowserTypeOpera', // 3
'BrowserTypeSafari', // 4
'BrowserTypeFirefox', // 5
'BrowserTypeChrome', // 6
)); // BrowserType as Increment
$browser_type = BrowserTypeChrome;
if($browser_type == BrowserTypeOpera) {
// Make Opera Adjustments (will not execute)
} else
if($browser_type == BrowserTypeChrome) {
// Make Chrome Adjustments (will execute)
}
enum(array(
'SearchTypeUnknown', // 0
'SearchTypeMostRecent', // 1 << 0
'SearchTypePastWeek', // 1 << 1
'SearchTypePastMonth', // 1 << 2
'SearchTypeUnanswered', // 1 << 3
'SearchTypeMostViews', // 1 << 4
'SearchTypeMostActive', // 1 << 5
), true); // SearchType as BitWise
$search_type = SearchTypeMostRecent + SearchTypeMostActive;
if($search_type & SearchTypeMostRecent) {
// Search most recent files (will execute)
}
if($search_type & SearchTypePastWeek) {
// Search files from the past will (will not execute)
}
if($search_type & SearchTypeMostActive) {
// Search most active files AS WELL (will execute as well)
}
不。
你将不得不使用数组，或者，如果你需要一些具有自定义类型，类和对象的东西。
你可以用常量做类似的事情，但它与专用枚举不同。
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