String replace file content with patterns

2018-06-09 17:41:51

With PowerShell, I want to read a text file like

number,
number(2),
number(3),
number(12,4),
number(17,4),

Find all matches to number(n,n) in the file and replace it to decimal(n,n) . What is the easiest way to do this with PowerShell?

一个班轮：

(gc .input.txt) -replace "number((d+,d+))", 'decimal$1' | Out-File output.txt

如果您只想在有十进制值（xx，yy）的地方更改字数，您可以这样做：

Get-Content "old file.txt" | ForEach-Object {
  $_ -replace 'number((d+,d+))','decimal$1'
} | Out-File "new file.txt"

你只是想要替换的单词number与decimal ？

Get-Content "old file.txt" | ForEach-Object {
  $_ -replace "number","decimal"
} | Out-File "new file.txt"

链接地址: http://www.djcxy.com/p/29116.html