在PHP中更改XML节点元素值并保存文件
<testimonials>
<testimonial id="4c050652f0c3e">
<nimi>John</nimi>
<email>test@test.com</email>
<text>Some text</text>
<active>1</active>
</testimonial>
<testimonial id="4c05085e1cd4f">
<name>ats</name>
<email>some@test.ee</email>
<text>Great site!</text>
<active>0</akctive>
</testimonial>
</testimonials>
我有这个XML strcuture，我需要找到具有特定id的证言并更改它的值并保存文件。 我有一个PHP脚本根据它的ID删除特定的证言：
<?php
$xmlFile = file_get_contents('test.xml');
$xml = new SimpleXMLElement($xmlFile);
$kust_id = $_GET["id"];
foreach($xml->testimonial as $story) {
if($story['id'] == $kust_id) {
$dom=dom_import_simplexml($story);
$dom->parentNode->removeChild($dom);
$xml->asXML('test.xml');
header("Location: newfile.php");
}
}
?>
您可以使用XPath来查找特定的元素。 SimpleXMLElement-> xpath（）返回（匹配）SimpleXMLElement对象的数组，即您可以像访问“您的”foreach循环一样访问和更改每个元素的数据。
<?php
// $testimonials = simplexml_load_file('test.xml');
$testimonials = new SimpleXMLElement('<testimonials>
<testimonial id="4c050652f0c3e">
<nimi>John</nimi>
<email>test@test.com</email>
<text>Some text</text>
<active>1</active>
</testimonial>
<testimonial id="4c05085e1cd4f">
<name>ats</name>
<email>some@test.ee</email>
<text>Great site!</text>
<active>0</active>
</testimonial>
</testimonials>');
// there can be only one item with a specific id, but foreach doesn't hurt here
foreach( $testimonials->xpath("testimonial[@id='4c05085e1cd4f']") as $t ) {
$t->name = 'LALALA';
}
echo $testimonials->asXML();
// $testimonials->asXML('test.xml');
版画
<?xml version="1.0"?>
<testimonials>
<testimonial id="4c050652f0c3e">
<nimi>John</nimi>
<email>test@test.com</email>
<text>Some text</text>
<active>1</active>
</testimonial>
<testimonial id="4c05085e1cd4f">
<name>LALALA</name>
<email>some@test.ee</email>
<text>Great site!</text>
<active>0</active>
</testimonial>
</testimonials>