解析嵌套的JSON响应Python
这个问题在这里已经有了答案:
您可以使用字典对象中的keys方法来获取密钥,然后迭代以获取所需的值。
例:
d = {
"available_projects": {
"model001": {
"available_models": [
"model_20171004-090552"
],
"status": "ready"
},
"model002": {
"available_models": [
"model_20171013-143108"
],
"status": "ready"
},
"model002b": {
"available_models": [
"model_20171013-151458"
],
"status": "ready"
}
}
}
for i in d["available_projects"].keys():
print i, "=" , d["available_projects"][i]['available_models'][0]
输出:
model001 = model_20171004-090552
model002b = model_20171013-151458
model002 = model_20171013-143108
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