HttpClient抛出ssl错误，但webview和HttpsURLConnection没有

所以我使用服务器（谷歌应用程序引擎）在客户端应用程序进行身份验证。 当我使用JavaFX的Webview或HttpsURLConnection一切顺利，他们连接，但是当我使用HttpClient它会引发以下错误

javax.net.ssl.SSLPeerUnverifiedException：未通过org.apache.http.conn.ssl.AbstractVerifier.verify处的sun.security.ssl.SSLSessionImpl.getPeerCertificates（Unknown Source）对peer进行身份验证（位于org.apache的AbstractVerifier.java:128） .http.conn.ssl.SSLSocketFactory.connectSocket（SSLSocketFactory.java:339）at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection（DefaultClientConnectionOperator.java:123）at org.apache.http.impl.conn.AbstractPoolEntry .Open（AbstractPoolEntry.java:147）at org.apache.http.impl.conn.AbstractPooledConnAdapter.open（AbstractPooledConnAdapter.java:108）at org.apache.http.impl.client.DefaultRequestDirector.execute（DefaultRequestDirector.java:415） ）在org.apache.http.impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:576）org.apache.http.impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:641）at org.apache.http。 impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:554）

完整的SSL报告在这里

我正在使用的代码

System.out.println("I started");
        String https_url = "https://app.quagrum.com";
          URL url;
          try {

             url = new URL(https_url);
             HttpsURLConnection con = (HttpsURLConnection)url.openConnection();//Works 
             System.out.println("I ran?");
    }
          catch(Exception a)
          {

          }
    try {
        HttpGet get = new HttpGet("https://app.quagrum.com");
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response = httpclient.execute(get);//Throws error
        System.out.println(response.getStatusLine().getStatusCode());
        if(response.getStatusLine().getStatusCode()!=200)
        {
            HttpEntity entity = response.getEntity();

            if (entity != null) {
                InputStream instream = entity.getContent();
                try {
                    Scanner s = new Scanner(instream).useDelimiter("A");
                    String result = s.hasNext() ? s.next() : "";
                    System.out.println(result);
                    result =result.substring(result.indexOf(""",7));
                    result=result.substring(0, result.indexOf("""));
                    System.out.println(result);
                } finally {
                    instream.close();
                }
            }
        }
        }catch(Exception a)
        {
            a.printStackTrace();
        }
    }

---

现在它运作正常。 没关系，Java让我完全重新设计我的程序的一部分，然后在稍后的版本中使用它

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