获取联系人的姓氏和名字而不是单个显示名称？
我目前正在使用Android联系人内容提供者，目前可以使用以下代码访问联系人完整显示名称而不会造成问题：
String[] PROJECTION = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
};
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
String SELECTION = "LOWER(" + ContactsContract.Contacts.DISPLAY_NAME + ")"
+ " LIKE '" + constraint + "%' " + "and " +
ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
Cursor cur = managedQuery(ContactsContract.Contacts.CONTENT_URI,
PROJECTION, SELECTION, null, sortOrder);
不过，我希望能够分别获得联系人姓氏和姓氏，我试图使用StructuredName试图获得这个，但我似乎无法得到它的工作。
任何人都可以正确地指出我如何正确使用StructuredName来将名称拆分为First和Last？
更新：
根据hovanessyan的建议，我尝试了以下几点：
String[] PROJECTION = new String[] {
ContactsContract.Data._ID,
ContactsContract.Data.DISPLAY_NAME,
ContactsContract.Data.HAS_PHONE_NUMBER,
};
String SELECTION = ContactsContract.CommonDataKinds.StructuredName.IN_VISIBLE_GROUP + " = '1'";
String sortOrder = ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
Cursor cursor = getContentResolver().query(ContactsContract.Data.CONTENT_URI, PROJECTION, SELECTION, null, sortOrder);
int indexGivenName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
int indexFamilyName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME);
int indexDisplayName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME);
while (cursor.moveToNext()) {
String given = cursor.getString(indexGivenName);
String family = cursor.getString(indexFamilyName);
String display = cursor.getString(indexDisplayName);
Log.e("XXX", "Name: | " + given + " | " + family + " | " + display);
}
但是，使用PROJECTION会导致崩溃，如下所示：
12-08 16:52:01.575: E/AndroidRuntime(7912): Caused by: java.lang.IllegalArgumentException: Invalid column has_phone_number
如果我删除了PROJECTION，我会打印出所有的结果，但很多都包含NULL。
例如：
12-08 16:56:14.055: E/XXX(8155): Name: | null | null | null
12-08 16:56:14.055: E/XXX(8155): Name: | null | null | null
12-08 16:56:14.055: E/XXX(8155): Name: | null | null | null
12-08 16:56:14.055: E/XXX(8155): Name: | null | null | null
所以任何人都可以看到我做错了，我的PROJECTION不起作用？
进一步更新：
我已经用我的PROJECTION对问题进行了整理，但是现在我遇到了一个问题，即DATA内容提供程序向我提供所有空数据并在我的代码中导致NULL指针异常。
来自ContactsContract.Contacts的游标计数让我回到115例如，但使用DATA表给我回464使用相同的参数，这导致我的应用程序中的巨大问题。
任何人有任何想法，为什么这是？
看看ContactsContract.CommonDataKinds.StructuredName类。 你在那里有所有必要的专栏，你也可以做一些事情：
Cursor cursor = contentResolver.query(ContactsContract.Data.CONTENT_URI, other_query_params_for_filtering);
int indexGivenName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
int indexFamilyName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME);
int indexDisplayName = cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME);
while (cursor.moveToNext()) {
String given = cursor.getString(indexGivenName);
String family = cursor.getString(indexFamilyName);
String display = cursor.getString(indexDisplayName);
}
Cursor phone_cursor = cr.query(ContactsContract.CommonDataKinds.
Phone.CONTENT_URI, null, null, null, null);
while (phone_cursor.moveToNext()) {
try {
int id = Integer.parseInt(phone_cursor.getString(phone_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.Phone.CONTACT_ID)));
Cursor name_cursor = cr.query(ContactsContract.Data.CONTENT_URI,null,
ContactsContract.Data.CONTACT_ID + " = " + id, null, null);
String name = phone_cursor.getString(phone_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String first_name ="";
String last_name = "";
while (name_cursor.moveToNext()) {
if(name_cursor.getString(name_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME))!=null){
first_name = name_cursor.getString(name_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME));
last_name = name_cursor.getString(name_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
}}
name_cursor.close();
String phoneNumber = phone_cursor.getString(phone_cursor.getColumnIndex
(ContactsContract.CommonDataKinds.Phone.NUMBER));
} catch (Exception e) {
}
}
phone_cursor.close();
以下是从ContactsContract.Data表中获取用户数据的一般功能：
Map<String, String> result = new HashMap<>();
Cursor cursor = context.getContentResolver().query(ContactsContract.Data.CONTENT_URI, null, ContactsContract.Data.CONTACT_ID + "='" + YOUR_CONTACT_ID + "'", null, null);
if (cursor != null) {
while (cursor.moveToNext()) {
String mime = cursor.getString(cursor.getColumnIndex(ContactsContract.Data.MIMETYPE));
switch (mime) {
case ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE:
result.put(FIRST_NAME, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME)));
result.put(LAST_NAME, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME)));
break;
case ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_ITEM_TYPE:
result.put(CITY, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.CITY)));
result.put(STREET, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.STREET)));
result.put(ZIP, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.POSTCODE)));
break;
case ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE:
if (ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE == cursor.getInt(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE))) {
result.put(MOBILE, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)));
}
break;
}
}
cursor.close();
}
return result;
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