How to get the filename without the extension from a path in Python?
How to get the filename without the extension from a path in Python?
I found out a method called os.path.basename to get the filename with extension. But even when I import os, I am not able to call it path.basename . Is it possible to call it as directly as basename?
Getting the name of the file without the extension :
import os
print(os.path.splitext("path_to_file")[0])
As for your import problem, you solve it this way :
from os.path import basename
# now you can call it directly with basename
print(basename("/a/b/c.txt"))
滚动它：
>>> import os
>>> base=os.path.basename('/root/dir/sub/file.ext')
>>> base
'file.ext'
>>> os.path.splitext(base)
('file', '.ext')
>>> os.path.splitext(base)[0]
'file'
>>> print os.path.splitext(os.path.basename("hemanth.txt"))[0]
hemanth
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