Method executed prior to Default Constructor

This question already has an answer here:

Are fields initialized before constructor code is run in Java? 4 answers

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Instance variable initialization expressions such as int var = getVal(); are evaluated prior to the constructor execution. Therefore getVal() is called before the constructor is executed.

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Constructor is called prior to method. The execution of method occurs after that which is a part of object creation in which instance variables are evaluated. This could be better understand from following code.

class SuperClass{
    SuperClass(){
        System.out.println("Super constructor");
    }
}
public class ChkCons extends SuperClass{

    int var = getVal();

    ChkCons() {
        System.out.println("I'm Default Constructor.");
    }

    public int getVal() {
        System.out.println("I'm in Method.");
        return 10;
    }

    public static void main(String[] args) {

        ChkCons c = new ChkCons();

    }

}

The above code has following output

Super constructor
I'm in Method.
I'm Default Constructor.

Here the compiler automatically adds super(); as the first statement in ChkCons() constructor, and hence it is called prior to the getVal() method.

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Whenever you create an instance of a class instance variables are initialized first followed by execution of the Constructor

Ref : Are fields initialized before constructor code is run in Java?

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