How to find substring inside a string (or how to grep a variable)?
I'm using BASH, and I don't know how to find a substring. It keeps failing, I've got a string (should this be an array?)
Below, LIST is a string list of database names, SOURCE is the reply, one of those databases. The following still doesn't work:
echo "******************************************************************"
echo "* DB2 Offline Backup Script *"
echo "******************************************************************"
echo "What's the name of of the database you would like to backup?"
echo "It will be named one in this list:"
echo ""
LIST=`db2 list database directory | grep "Database alias" | awk '{print $4}'`
echo $LIST
echo ""
echo "******************************************************************"
echo -n ">>> "
read -e SOURCE
if expr match "$LIST" "$SOURCE"; then
echo "match"
exit -1
else
echo "no match"
fi
exit -1
I've also tried this but doesn't work:
if [ `expr match "$LIST" '$SOURCE'` ]; then
LIST="some string with a substring you want to match"
SOURCE="substring"
if echo "$LIST" | grep -q "$SOURCE"; then
echo "matched";
else
echo "no match";
fi
你也可以比较通配符：
if [[ "$LIST" == *"$SOURCE"* ]]
如果你使用bash，你可以说
if grep -q "$SOURCE" <<< "$LIST" ; then
...
fi