使用Linux shell脚本在字符串中定位字符串?
如果我在shell变量中有文本,请说$a
:
a="The cat sat on the mat"
如何搜索“cat”并使用Linux shell脚本返回4,如果找不到则返回-1?
用bash
a="The cat sat on the mat"
b=cat
strindex() {
x="${1%%$2*}"
[[ "$x" = "$1" ]] && echo -1 || echo "${#x}"
}
strindex "$a" "$b" # prints 4
strindex "$a" foo # prints -1
您可以使用grep来获取字符串匹配部分的字节偏移量:
echo $str | grep -b -o str
按照你的例子:
[user@host ~]$ echo "The cat sat on the mat" | grep -b -o cat
4:cat
如果你只想要第一部分,你可以通过管道来awk
echo $str | grep -b -o str | awk 'BEGIN {FS=":"}{print $1}'
我为此使用了awk
a="The cat sat on the mat"
test="cat"
awk -v a="$a" -v b="$test" 'BEGIN{print index(a,b)}'
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